# Limits: Find the limit of [x – 3/ x^2 – 9]; lim x -> 3?-Collection of common programming errors

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discoverer: anonymous Find the limit of [x – 3/ x^2 – 9]; lim x -> 3

I worked this problem and got f(x) 1/(3 – x) ; which is undefined. Did anyone get any thing different? Your help is always appreciated!

- Well, firstly the limit can be re-written as: limit of [x – 3/ (x+3)(x – 3)]; lim x -> 3 which can be simiplified to: limit of [1/ x+3]; lim x -> 3
Hence the limit is 1/6.

- (x – 3) / (x² – 9) = (x – 3) / [(x – 3)(x + 3)] = 1 / (x + 3)
lim [1 / (x + 3)] as x –> 3 = 1/6

Source of the problem： answers.yahoo

Web site is in building

Originally posted 2013-11-09 21:40:18.