If the line tangent to the graph of the function f at point (1,7) passes through the point (-2,-2)?-Record and share programming errors

• Since line through points (1,7) and (−2,−2) is tangent to graph of f at point (1,7) f'(1) = slope from point (1,7) to point (−2,−2) f'(1) = (7+2)/(1+2) = 3

  Answer: C)

• The tangent line goes through (1,7) and (-2,-2) Lets call the line y = mx + c, and substitute in these known values 7 = m*1 + c -2 = m* (-2) + c Subtract second eqn from first 9 = 3m m=3 So the slope of the tangent is 3.

  Answer C)

Originally posted 2013-08-31 07:31:19.